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(B) The preparation of ethers via the Williamson ether synthesis involves the reaction of an alkoxide or phenoxide ion with an alkyl halide. For the s

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$C_6H_5O^{(-)} Na^{(+)} + C_6H_5CH_2Cl$

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(B) The preparation of ethers via the Williamson ether synthesis involves the reaction of an alkoxide or phenoxide ion with an alkyl halide. For the synthesis of phenyl benzyl ether $(C_6H_5OCH_2C_6H_5)$,we need a nucleophilic substitution reaction. Option $B$ involves the reaction of sodium phenoxide $(C_6H_5O^{(-)} Na^{(+)})$ with benzyl chloride $(C_6H_5CH_2Cl)$. Benzyl chloride is a primary alkyl halide and is highly reactive towards $S_N2$ reactions due to the resonance stabilization of the transition state by the phenyl group. In contrast,option $A$ involves chlorobenzene,which is unreactive towards $S_N2$ reactions because the $C-Cl$ bond has partial double bond character and the phenyl ring is electron-rich,hindering nucleophilic attack. Therefore,the reaction $C_6H_5O^{(-)} Na^{(+)} + C_6H_5CH_2Cl \rightarrow C_6H_5OCH_2C_6H_5 + NaCl$ is the most efficient method.

Which of the following procedures would be best for the preparation of phenyl benzyl ether? $C_6H_5OCH_2C_6H_5$

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